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4=3x^2-10x-9
We move all terms to the left:
4-(3x^2-10x-9)=0
We get rid of parentheses
-3x^2+10x+9+4=0
We add all the numbers together, and all the variables
-3x^2+10x+13=0
a = -3; b = 10; c = +13;
Δ = b2-4ac
Δ = 102-4·(-3)·13
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-16}{2*-3}=\frac{-26}{-6} =4+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+16}{2*-3}=\frac{6}{-6} =-1 $
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